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Re: security question
From: |
Phil R Lawrence |
Subject: |
Re: security question |
Date: |
Fri, 13 Dec 2002 10:01:57 -0500 |
User-agent: |
Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.0.1) Gecko/20021003 |
Steven Tryon wrote:
> On Thu, 2002-12-12 at 10:51, Phil R Lawrence wrote:
>
>>I saw in the docs how to set up pserver and how it can
>>manage read-write permissions. But I won't run a server
>>without encryption.
>
We run pserver on a machine behind a firewall and access with redirected
ports with ssh.
Someone posted on this list a cookbook ssh command to do so...
ssh address@hidden -L 2401:host.whatever.com:2401
Then set your CVSROOT to point to localhost.
OK. I can follow the cookbook above for client access from windows and
linux, but how can I establish that same mapping for developers when
they are already logged onto the machine with the repository? i.e., how
can a developer on localhost log into the pserver using SSH?
Phil
PS: Does this look right?
/etc/passwd:
lskywalk:x:600:600:Luke Skywalker:/home/lskywalk:/bin/bash
cvs-lsky:x:601:601:Luke Skywalker:/home/usr/local/cvs:/bin/false
askywalk:x:600:600:Anakin Skywalker:/home/askywalk:/bin/bash
cvs-asky:x:601:601:Anakin Skywalker:/home/usr/local/cvs:/bin/false
/etc/group:
cvs-fooproj:x:600:cvs-lsky
cvs-barproj:x:600:cvs-lsky,cvs-asky
CVSROOT/passwd:
lskywalk:nnnnnnnnnn:cvs-lsky
askywalk:nnnnnnnnnn:cvs-asky
THEN:
# chgrp -R cvs-fooproj /usr/local/cvs/fooproj
# chmod g+srwx /usr/local/cvs/fooproj
# chmod o+rx /usr/local/cvs/fooproj
# chmod o-w /usr/local/cvs/fooproj
- Re: binaries, (continued)
- Re: binaries, david, 2002/12/11
- Re: binaries, Phil R Lawrence, 2002/12/11
- Re: binaries, Mike Ayers, 2002/12/12
- security question, Phil R Lawrence, 2002/12/12
- Re: security question, Larry Jones, 2002/12/12
- Re: security question, Noel Yap, 2002/12/12
- Re: security question, Frederic Brehm, 2002/12/12
- Re: security question, Geoff Beier, 2002/12/12
- Re: security question, Steven Tryon, 2002/12/12
- Re: security question, Noel Yap, 2002/12/13
- Re: security question,
Phil R Lawrence <=