Re: Translating ODE from Matlab to Octave

[Bård Skaflestad]

On Tue, 2013-11-26 at 17:05 +0100, c. wrote:
> On 26 Nov 2013, at 16:54, Bård Skaflestad <address@hidden> wrote:
> 
> > Alternatively, you *could* use
> > 
> >        [y, t] = lsode(@(y, t) f(t, y), y0, t)
> > 
> > if you don't want to change the definition of 'f'.
> 
> no, you can't call 'lsode' like that. 
> 
> 'lsode' does not return the time vector 't',

Thanks a lot for alerting me to that fact.  Now I just have to ask
myself why I didn't derive that conclusion from the documentation...

> the calling sequence is different from ode15s. the set of times at
>  which you want your solution evaluate should be passed as an input
>  parameter.

Are you saying that LSODE does not support automatic step size selection
or does the solver "simply" not expose the selected time steps to the
caller?


Sincerely,
-- 
Bård Skaflestad <address@hidden>
SINTEF ICT, Applied mathematics