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Re: Implementing a Jacobi iterative method for Ax=b


From: Joza
Subject: Re: Implementing a Jacobi iterative method for Ax=b
Date: Mon, 29 Oct 2012 06:16:38 -0700 (PDT)

Here are A and b if you want to test it out!

A = [ 3 12 0 -1 0 0; 4 0 31 1 0 0; 2 1 0 0 17 -3; 27 2 0 0 0 1; 0 0 0 -1 1
11; 0 0 0 24 -1 0 ]

(6x6)

b = [ 39 117 12 98 14 55]^T

(6x1)



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