Re: multiplication by zero

[James Sherman Jr.]

It will always be evaluated.  It has to simply because 0 times something isn't always 0.  The specific case I'm thinking of is 0*NaN is NaN not 0.

On Tue, May 18, 2010 at 12:13 PM, mmasny <address@hidden> wrote:

I have such an _expression_:
x=5;
y = 0 * f(x);

Will the value of f(x) be computed? What if it were .* instead of *? What if
I had y = f(x) * 0?
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