Re: precision for discharge function

[Primoz PETERLIN]

Hi,

You probably want u=U0*exp(-t/T), not u=U0*exp(-t*T).

Regards, Primož

2009/6/9 feldmaus <address@hidden>:
> Hi All,
>
> today i tried to plot an discharge function:
> T=1e-6
> t=0:0.1e-6:10e-6;
> U0=1
> u=U0*exp(-t*T);
> plot(t,u)
>
> But i pnly get a horizontal line. :-(
>
> This is because of the precision i think, so how
> can i still plot it ?
>
> regards Markus
>
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> Help-octave mailing list
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-- 
Primož Peterlin,   Inštitut za biofiziko, Med. fakulteta, Univerza v Ljubljani
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