A thing about exponentials.

[Jordi Gutierrez Hermoso]

Apologies if this is a FAQ, but I couldn't find it in the FAQ, and I
tried a few searches in the mailing list archive to no avail.

In Octave 0^(1+i) is 0 and 0^i is NaN. They're both NaN in Matlab.

I can understand the NaN... probably from a call to log(0) somewhere.
But why isn't 0^(1+i) also NaN in Octave? What is Octave doing to
avoid that call to log(0)?

Thanks!
- JGH



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