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Re: average of a function
From: |
Paul Kienzle |
Subject: |
Re: average of a function |
Date: |
Tue, 9 Nov 2004 04:16:17 -0500 |
On Nov 8, 2004, at 10:36 PM, Fred J. wrote:
I need to determine the average value of this function
which I expect
it to be -1.620993 but I am getting a different ans
and not sure if I am
using octave correctly.
octave> function y=x(t), y = t^2 - 5*t + 6*cos(pi*t);
end;
octave> quad('x', -1, 5/2)
ans = -5.6735
octave:5> format long
octave:6> quad('x', -1, 5/2)/(5/2 - -1)
ans = -1.62099257606588
- Paul
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