Re: Passing a function as parameter

[Dan Boghiu]

Define your function "mean" in this way:

function y = mean(f, a, b)
  y = (feval(f, a) + feval(f, b))/2.0;
endfunction

and then try:
    mean('foo', 2, 3)


Dan




----- Original Message ----- 
From: "Luca Manini" <address@hidden>
To: <address@hidden>
Sent: Friday, November 16, 2001 10:50
Subject: Passing a function as parameter


> Hi, 
> 
> is it possible to pass functions to other fucntions?
> The simple example is to write a function that calculate the 
> mean (or the definite integral) of that function on a given interval.
> 
> in Python is like this:
> 
> def foo(x):
>     return x * x
> 
> def mean(f, a, b):
>     return (f(a) + f(b))/2.0
> 
> print mean(foo, 5, 0)
> 
> in Octave "should" be something like:
> 
> function y = foo(x)
>   y = x * x;
> endfunction
> 
> function y = mean(f, a, b)
>   y = (f(a) + f(b))/2.0;
> endfunction
> 
> mean (foo, 5, 0)
> 
> or 
> 
> mean ('foo', 5, 0)
> 
> but it does not work. 
> 
> 
> Any hint? TIA, Luca.
>         Please answer (also) directly to address@hidden
> 
> 
> 
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Octave is freely available under the terms of the GNU GPL.

Octave's home on the web:  http://www.octave.org
How to fund new projects:  http://www.octave.org/funding.html
Subscription information:  http://www.octave.org/archive.html
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