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Inf/Inf = NaN?
From: |
John Utz |
Subject: |
Inf/Inf = NaN? |
Date: |
Wed, 16 Apr 1997 22:42:53 -0700 (PDT) |
Hello everybody;
On my fake pentium-100 running FreeBSD-2.2-GAMMA and octave-2.0.5 compiled
with gcc-2.7.2 i get the above result ( Inf/Inf = NaN ). Shouldn't this
equal 1?
I was thinking of hacking if(a==Inf)&&(b==Inf) result = 1 into my
code, but this is not how i like to work.
note, the specific operation is (Inf-foo)/(Inf+foo) where foo is a real
positive int. This should be equal to 1, but...does the fact that i am
performing operations on Inf cause the math to "throw up it's hands and
surrender", so to speak?
tnx!
john
*******************************************************************************
John Utz address@hidden
idiocy is the impulse function in the convolution of life
- Inf/Inf = NaN?,
John Utz <=