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## Re: [Help-gsl] hi :-) \o/ I've some problem with eigensystem

**From**: |
Giuseppe Marco Randazzo |

**Subject**: |
Re: [Help-gsl] hi :-) \o/ I've some problem with eigensystem |

**Date**: |
Thu, 22 Apr 2010 12:00:58 +0200 |

**User-agent**: |
KMail/1.13.2 (Linux/2.6.33-gentoo-r1; KDE/4.4.2; x86_64; ; ) |

On Thursday 22 April 2010 10:20:39 tuc wrote:
>* let A be a square matrix. then a eigenvector v to the eigenvalue a is*
>* defined to have the property:*
>* A*v=a*v.*
>* *
>* therefor for any real number x (nonzero, zero is never an eigenvector)*
>* x*v is also a eigenvector of A:*
>* A*(x*v)=x*(A*v)=x*(a*v)=a*(x*v)*
>* *
>* and since (-1) is a real number, mathematically speaking both results*
>* are correct.*
>
ok :-) thanks in advance for the answer. Maybe i've understood. so it seems to
be equal...but are symmetric and opposite values
-0.735179 != 0.735179
but:
abs( -0.735179 ) = abs( 0.735179 )
so :| i'm just think that if i use the value -1 for x and the value 1 the
eigenvectors which i get are symmetric and opposite in sign no?
:)