Inline Assembly

[scarvenger]

The following code seems to be considered ilegal in GCC, why?

movb 2(%1, %%ecx), (%0, %%ecx);

Why when i try to compile my program with the following code and the option
-O3 the compiler says to me that the symbol bgrLoop was already defined?

    __asm__ __volatile__ (
         "xorl %%ecx, %%ecx;"
         "bgrLoop:;"
         "movb  (%1, %%ecx), %%al;"
         "movb 2(%1, %%ecx), %%ah;"
         "movb %%al, 2(%0, %%ecx);"
         "movb %%ah,  (%0, %%ecx);"
         "addl $3, %%ecx;"
         "decl %2;"
         "jnz bgrLoop;" : "=r" (buffer) : "r" (buffer), "r" (size) : "ah",
"al", "ecx");

Felipe
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