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warning with function templates
From: |
Christian Christmann |
Subject: |
warning with function templates |
Date: |
Sat, 16 Jul 2005 14:58:17 +0200 |
Hi,
when I run this code:
#include <iostream>
using namespace std;
template <class T>
T GetValue(int a)
{
if (a = 1)
return 1;
else
return 2.55; // line 11
}
int main()
{
int a = GetValue<int>(1); // line 16
cout << "\nInt a : " << a << endl;
double b = GetValue<double>(2);
cout << "\nDouble b: " << b << endl;
return 0;
}
I get the gcc warning:
temp.cpp: In function `T GetValue(int) [with T = int]':
temp.cpp:16: instantiated from here
temp.cpp:11: warning: converting to `int' from `double'
Why?
Line 16 should not be reached when the function is called
from line 11.
Is there any way to avoid this warning?
Thank you
Chris
- warning with function templates,
Christian Christmann <=