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From: | Andreas Röhler |
Subject: | Re: print out all members of a list |
Date: | Tue, 01 Mar 2011 12:44:18 +0100 |
User-agent: | Mozilla/5.0 (X11; U; Linux i686; de; rv:1.9.1.11) Gecko/20100711 Thunderbird/3.0.6 |
Am 28.02.2011 16:20, schrieb ken:
(car '("one" "two" "three")) prints out "one" ... the first of the list. How to print out all elements of the list (in order and with the double quotes around them? I'm actually looking just to substitute something for "car" and not write an entire function. Or is there no such thing? Thanks much.
and still a form delivering with doublequotes... (let ((my-list (list "one" "two" "three"))) (dolist (elem my-list) (insert (format "\n\"%s\"" elem))))
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