Re: [2nd attempt] What's the doc of replace-regexp-in-string saying ?

[Bill Marcum]

On 2010-11-22, bolega <gnuist006@gmail.com> wrote:
> Hello All,
>
> I am posting my question a second time. first time around, it was the
> victim of the humor of come cynics.
>
> Bolega
>
> On Nov 21, 3:27 pm, bolega <gnuist...@gmail.com> wrote:
>> Hello All,
>>
>> In this doc, its not clear what the role of \' is ?
>>
>>
>> To replace only the first match (if any), make REGEXP match up to \'
>> and replace a sub-expression, e.g.
>>   (replace-regexp-in-string "\(foo\).*\'" "bar" " foo foo" nil nil 1)
>>     => " bar foo"
>
This is off topic for comp.unix.shell, but it seems clear to me. If the 
regexp didn't end with \', it would change " foo foo" to " bar bar".


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