Re: Non-Commutative calculations in Calc, Revisited

[David Kastrup]

Jay Belanger <belanger@truman.edu> writes:

> Neon Absentius <absent@sdf.lonestar.org> writes:
>
>> When in non-commutative (aka `matrix') mode calc calculates 
>> (a b)^-1 to be a^-1 b^-1 instead of the correct b^-1 a^-1.

Uh, what's correct about b^-1 a^-1?

Set a=[1,1], b=[1;0], then (a b)^-1 = [1], and neither b^-1 nor a^-1
exist.

This only works with a and b being square matrices.

-- 
David Kastrup, Kriemhildstr. 15, 44793 Bochum