[Help-bash] eval and set -e

[Peng Yu]

Hi,

I have the following code.

The exit code of the first eval is 1. The exit code of the second eval
is supposed to be 1 as well, so I'd expect the last echo to print the
exit code. But I don't see it.

Does anybody know how to understand this code?

$ cat main.sh
#!/usr/bin/env bash
# vim: set noexpandtab tabstop=2:

( eval 'set -e; false; echo xx' )
echo xxx "$?"
( eval 'set -e; false; echo xx' ) || echo "$?"
$ ./main.sh
xxx 1
xx

-- 
Regards,
Peng