Re: how having the basename of a file or directory

[Stephen J. Turnbull]

Thierry Volpiatto writes:

 > (file-name-nondirectory "path/to/a/directory")
 > should return ==> directory
 > (file-name-nondirectory "path/to/a/file")
 > should return ==> file

They do.

(file-name-nondirectory "path/to/a/directory/") => ""

is the problem.

 > So modifying `file-name-nondirectory'

This is probably out of the question.  It should be the case that

(equal fname (concat (file-name-directory fname)
                     (file-name-nondirectory fname))))

 > or creating a basename function

Un-Pythonic.  But then, this isn't Python, so I guess it's OK. ;-)