Re: Calc: `*' binds more strongly than `/'

[Christian Schlauer]

Stefan Monnier <address@hidden> writes:

>> Exactly; the motivation was for the implicit multiplication, but he
>> didn't want to give implicit and explicit multiplication different
>> precedences.
>
> And that's where he went wrong IMNSHO.

I agree with Stefan -- it seems that implicit multiplication a.k.a.
the `juxtaposition operator' is assumed by default, even when a `*' is
given as in `y = 3/2*x'. Calc sort of strips the `*' and calculates `y
= 3/(2x)'.

I'm glad you found the root of the `feature'!