Re: [Chicken-users] Syntax of case expressions

[Ivan Raikov]

  Yes. My apologies for screwing up something so simple to correct a
simple mistake :-) 

Here is the relevant part of R5RS:

Literal expressions
-------------------

 - syntax: quote <datum>
 - syntax: ' <datum>
 - syntax: <constant>

     `(quote <datum>)' evaluates to <datum>.  <Datum> may be any
     external representation of a Scheme object.  This notation is
     used to include literal constants in Scheme code.


     (quote a)                              ==>  a
     (quote #(a b c))                       ==>  #(a b c)
     (quote (+ 1 2))                        ==>  (+ 1 2)

     `(quote <datum>)' may be abbreviated as '<datum>.  The two
     notations are equivalent in all respects.

     'a                                     ==>  a
     '#(a b c)                              ==>  #(a b c)
     '()                                    ==>  ()
     '(+ 1 2)                               ==>  (+ 1 2)
     '(quote a)                             ==>  (quote a)
     ''a                                    ==>  (quote a)

     Numerical constants, string constants, character constants, and
     boolean constants evaluate "to themselves"; they need not be
     quoted.

     '"abc"                                 ==>  "abc"
     "abc"                                  ==>  "abc"
     '145932                                ==>  145932
     145932                                 ==>  145932
     '#t                                    ==>  #t
     #t                                     ==>  #t


Matt Gushee <address@hidden> writes:

> Ivan Raikov wrote:
>>   Oops, I meant that (define foo 'a) -> (define foo (quote a)).
>
> No wonder I was confused.