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Re: Target specific immediate append operator not working as expected


From: Paul D. Smith
Subject: Re: Target specific immediate append operator not working as expected
Date: Tue, 21 Feb 2006 12:55:40 -0500

%% <address@hidden> writes:

  lm> There is some weirdness going on with the append operator and
  lm> target-specific contexts.

  lm> The append operator should act immediately if the variable was
  lm> originally assigned with an immediate assignment but this does not
  lm> happen if the variable was globally assigned and the append is
  lm> target-specific, the append does variable expansion (as if the
  lm> variable had been deferred).

  lm> VAR := $$LOGNAME
  lm> bar: VAR += bar
  lm> foo bar:
  lm>         echo $(VAR)

  lm> colsw07m -> ~/src/make/make-3.81rc1/make bar
  lm> echo OGNAME bar
  lm> OGNAME bar

Hm.  I agree that the results seem incorrect.  Can you please file a bug
about this on the Savannah site?

However, I did spend some time looking at this and the fix is not that
simple.  In fact, the behavior was changed precisely BECAUSE the
previous behavior, while it apparently handled this case, didn't work in
other cases.

The way make works today for appended target-specific variables is: when
the variable is expanded all the parts are put into a buffer, and then
the entire buffer is expanded within the context of the target's
variables etc.

After the first step, the static variable has worked and the buffer has:

    $LOGNAME bar

in it.  However, then that buffer is expanded in the second step and you
lose the "$L".  By this time it's just a string and there's nothing to
say that one part shouldn't be expanded because it came from a simple
variable.


The obvious idea is to change it so that variables are expanded one at a
time, as they're added to the buffer, then not expand the string at the
end.  In fact, this is how make used to do it and why it used to work.
However, this fails in situations like this:

    FOO := foo
    BAR = one $(FOO)

    a: FOO := bar
    a: BAR += two $(FOO)
    a: ; @echo '$(BAR)'

Because of the recursive way make expands variables, if we evaluate the
global value of BAR (needed because of the += in the target-specific
value) when the value of FOO at that point is "foo" and you get output
of:

    one foo two bar

instead of what you'd expect, which is:

    one bar two bar


Fixing this is not that easy: basically we need to go back to expanding
variables as they're added, like we used to do it before, but instead of
expanding them within the context of their own variable set we have to
always expand them in the context of the file's variable set.  And we
have to be sure we don't loop infinitely :-).

I can't guarantee whether this will be fixed in 3.81, given that time is
so short and the change is not trivial.  We'll have to see.  But please
do file a bug on this so it won't get lost.

Thanks!

-- 
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 Paul D. Smith <address@hidden>          Find some GNU make tips at:
 http://www.gnu.org                      http://make.paulandlesley.org
 "Please remain calm...I may be mad, but I am a professional." --Mad Scientist




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