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Re: LONG_LONG_MIN


From: Jim Meyering
Subject: Re: LONG_LONG_MIN
Date: Mon, 08 Mar 2010 09:33:58 +0100

Bruno Haible wrote:
> Compiling a gnulib testdir on Solaris/x86 with Sun C, I get these errors:
>
> cc -O -xc99=all -DHAVE_CONFIG_H -DEXEEXT=\"\" -DEXEEXT=\"\" -DNO_XMALLOC  
> -DEXEEXT=\"\" -I. -I..  -I../intl  -I/home/haible/prefix-x86/include 
> -D_REENTRANT  -g -c -o xstrtoll.o xstrtoll.c
> "xstrtol.c", line 49: undefined symbol: LONG_LONG_MIN
> "xstrtol.c", line 54: undefined symbol: LONG_LONG_MAX
> cc: acomp failed for xstrtoll.c
> *** Error code 2
>
> cc -O -xc99=all -DHAVE_CONFIG_H -DEXEEXT=\"\" -DEXEEXT=\"\" -DNO_XMALLOC  
> -DEXEEXT=\"\" -I. -I..  -I../intl  -I/home/haible/prefix-x86/include 
> -D_REENTRANT  -g -c -o xstrtoull.o xstrtoull.c
> "xstrtol.c", line 54: undefined symbol: ULONG_LONG_MAX
> cc: acomp failed for xstrtoull.c
> *** Error code 2
>
> The reason is that the files strtol.c, xstrtoll.c, lib/xstrtoull.c use the
> macros LONG_LONG_MIN, LONG_LONG_MAX, ULONG_LONG_MAX. But these macros are
> not standard. ISO C99 and POSIX specify that <limits.h> defines
> LLONG_MIN, LLONG_MAX, ULLONG_MAX. The macros LONG_LONG_MIN, LONG_LONG_MAX,
> ULONG_LONG_MAX come from gcc's <limits.h>:
>
>
>   #if defined (__GNU_LIBRARY__) ? defined (__USE_GNU) : !defined 
> (__STRICT_ANSI__)
>   /* Minimum and maximum values a `signed long long int' can hold.  */
>   # undef LONG_LONG_MIN
>   # define LONG_LONG_MIN (-LONG_LONG_MAX - 1LL)
>   # undef LONG_LONG_MAX
>   # define LONG_LONG_MAX __LONG_LONG_MAX__
>
>   /* Maximum value an `unsigned long long int' can hold.  (Minimum is 0).  */
>   # undef ULONG_LONG_MAX
>   # define ULONG_LONG_MAX (LONG_LONG_MAX * 2ULL + 1ULL)
>   #endif
>
>
> As you can see, these are not even defined with "gcc -ansi".
>
> Suggestions? Should we use LLONG_MIN or better rely on the macros from
> <stdint.h>?

That looks like an oversight.
I suppose I've never noticed because coreutils no longer
uses any of those symbols.

Using LLONG_MIN etc. sounds fine.
Which macros from <stdint.h> would be better?




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