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From: | Florian Mayer |
Subject: | Re: Curious case of arithmetic expansion |
Date: | Sun, 23 Apr 2017 14:28:01 +0200 |
What I’m saying is, that if bash does recursively apply expansion mechanisms on the identifiers until it can retrieve a number, it should do it symmetrically. That is, it should remember what chain of expansion had been necessary for a particular number to appear at the end of the expansion. So instead of 124 moo 123 The echo command should produce bar moo 124 (The expansion chain here was foo->bar->moo->123) No it is really indirection. Bash even has a special (and very limited) syntax for that. Consider $ foo=bar; bar=moo You can get the string „moo“ through foo by using $ echo ${!foo} $ echo ${!!foo} # or something else does not work, though...
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