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Re: `declare -fp` mishandles heredoc with || statement
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From: |
Chris F.A. Johnson |
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Subject: |
Re: `declare -fp` mishandles heredoc with || statement |
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Date: |
Fri, 31 May 2013 23:27:06 -0400 (EDT) |
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User-agent: |
Alpine 2.02 (DEB 1266 2009-07-14) |
On Fri, 31 May 2013, Mike Frysinger wrote:
simple code snippet:
$ cat test.sh
func() {
cat > / <<EOF || echo FAIL
11
EOF
}
declare -fp
when run, we see the || statement is incorrectly moved to after the heredoc:
$ bash ./test.sh
func ()
{
cat > / <<EOF
11
EOF
|| echo FAIL
}
every version of bash i tried fails this way (2.05b through 4.2.45)
With 4.2.37:
func ()
{
cat > / <<EOF ||
11
EOF
echo FAIL
}
--
Chris F.A. Johnson, <http://cfajohnson.com/>
Author:
Pro Bash Programming: Scripting the GNU/Linux Shell (2009, Apress)
Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)