Commands executed with $($prog) do not run properly

[hgb]

Configuration Information [Automatically generated, do not change]:
Machine: i486
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='i486' 
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i486-pc-linux-gnu' 
-DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL 
-DHAVE_CONFIG_H   -I.  -I../bash -I../bash/include -I../bash/lib   -g -O2 -Wall
uname output: Linux main.hgbhome.net 2.6.18-4-686 #1 SMP Wed May 9 23:03:12 UTC 
2007 i686 GNU/Linux
Machine Type: i486-pc-linux-gnu

Bash Version: 3.2
Patch Level: 39
Release Status: release

Description:

Hi,

if a program ist started with $($prog) the output is different from <command>
or even $(<command>). Example with find (excluding a directory from search):

$ ls -l /test
total 16
drwxrwxr-x 2 hgb hgb 4096 Nov  6 02:14 a
drwxrwxr-x 2 hgb hgb 4096 Nov  6 02:14 b
drwxrwxr-x 2 hgb hgb 4096 Nov  6 02:14 c
drwxrwxr-x 2 hgb hgb 4096 Nov  6 02:14 d
$ find /test -type d ! -wholename "/test"
/test/c
/test/b
/test/d
/test/a
$ echo "$(find /test -type d ! -wholename "/test")"
/test/c
/test/b
/test/d
/test/a
$ prog='find /test -type d ! -wholename "/test"'
$ echo $prog
find /test -type d ! -wholename "/test"
$ echo "$($prog)"
/test
/test/c
/test/b
/test/d
/test/a
$

As seen above /test ist shown when $prog is executed.

I see the same behavior with
GNU bash, version 3.2.25(1)-release (x86_64-redhat-linux-gnu) (CentOS)
GNU bash, version 3.2.39(1)-release (i486-pc-linux-gnu) (debian)


I understand that the above looks crazy and not like a problem out of real life
.... I had to use find to crawl through a huge tree and remove only a few files
in it. I came across the above problem when feeding an array with the output of
find; I fixed it for now by removing the unwanted entries from the output
array.

Thanks in advance for looking into this.

Regards
        -- hgb