Re: Bash 3.2.25 not expanding subscript...

[Bernd Eggink]

Brad Diggs schrieb:

> In short the bug is the result of failure to expand the
> subscript of an array if the subscript is a variable.
> The following script should return a list of files with a 
> preceding (File <#>: ).  However, it does not work that 
> way because the integer variable (${d}) used in the subscript
> of the array statement (FileList[${d}]=${File}) does not get 
> properly expanded.
>
> #!/bin/bash
> declare -a FileList=('')
> declare -i d=0
>
> ls -1| while read File
> do
>    FileList[${d}]=${File}
>    d=$((10#${d}+1))
> done

This is normal bash behaviour, see FAQ E4. As bash executes _all_ parts 
of a pipe in subshells (in contrast to ksh, where the last component is 
executed in the current shell), the variable 'FileList' being assigned 
here is local to the subshell. After the loop the variable 'FileList' 
declared in line 1 (which happens to have the same name, but that 
doesn't matter) is unchanged.

Try this instead:

        while read File
        do
           FileList[d]=$File
           (( d=d+1 ))
        done <<<"$(ls -1)"

Greetings,
Bernd

--
Bernd Eggink
monoped@sudrala.de
http://sudrala.de