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bash -n doesn't seem to catch all syntax errors...
From: |
Ken Failbus |
Subject: |
bash -n doesn't seem to catch all syntax errors... |
Date: |
Mon, 15 Oct 2007 18:27:43 -0400 |
Hi Guys,
When I specify on command-line "bash -n <myscript name>". Bash doesn't
check for valid syntax errors. E.g. if variable is missing a "$" infront
of it while assigning a value. This is not catched by bash. Is there a
more specific option that should be specified to bash to check for
syntax errors.
Regards,
Ken
### example code
p=hello
e=world
If [ p != $e ];then
echo "not equal"
else
echo "equals"
fi
- bash -n doesn't seem to catch all syntax errors...,
Ken Failbus <=
- Re: bash -n doesn't seem to catch all syntax errors..., Jan Schampera, 2007/10/15
- Re: bash -n doesn't seem to catch all syntax errors..., Stephane Chazelas, 2007/10/16
- RE: bash -n doesn't seem to catch all syntax errors..., Ken Failbus, 2007/10/16
- RE: bash -n doesn't seem to catch all syntax errors..., Ken Failbus, 2007/10/16
- Re: bash -n doesn't seem to catch all syntax errors..., Andreas Schwab, 2007/10/16
- RE: bash -n doesn't seem to catch all syntax errors..., Ken Failbus, 2007/10/16
- Re: bash -n doesn't seem to catch all syntax errors..., Chet Ramey, 2007/10/16
- RE: bash -n doesn't seem to catch all syntax errors..., Ken Failbus, 2007/10/17