bash-3.0: brace expansion vs variable expansion

[Tim Waugh]

This short script:

var=baz
echo foo{bar,${var}.}
echo foo{bar,${var}}

gives the following output with bash-3.0:

./test: line 2: foo${var.}: bad substitution
foobar} foobaz

The output I expect, and which bash-2.05b gives, is:

foobar foobaz.
foobar foobaz

If I change the script to use '$var' instead of '${var}' it works
fine.

Tim.
*/

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