[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Invalid quoting in variable substitution.
From: |
Neal H. Walfield |
Subject: |
Invalid quoting in variable substitution. |
Date: |
Mon, 15 Mar 2004 12:54:39 -0500 |
User-agent: |
Wanderlust/2.8.1 (Something) SEMI/1.14.3 (Ushinoya) FLIM/1.14.3 (UnebigoryĆmae) APEL/10.3 Emacs/21.2 (i386-debian-linux-gnu) MULE/5.0 (SAKAKI) |
Configuration Information [Automatically generated, do not change]:
Machine: i386
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i386'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i386-pc-linux-gnu'
-DCONF_VENDOR='pc' -DSHELL -DHAVE_CONFIG_H -I. -I../bash -I../bash/include
-I../bash/lib -g -O2
uname output: Linux moore 2.4.22-1-686 #6 Sat Oct 4 14:09:08 EST 2003 i686
GNU/Linux
Machine Type: i386-pc-linux-gnu
Bash Version: 2.05b
Patch Level: 0
Release Status: release
Description:
Invalid quoting in variable substitution.
Repeat-By:
$ ls -1d *foo*
\"foo
foo
$ ls -1d *foo* | while read i; do ls -1d "$i"; done
ls: "foo: No such file or directory
foo
Fix:
Unknown at this time.
- Invalid quoting in variable substitution.,
Neal H. Walfield <=