This used to work, but now gives a SYNTAX ERROR
pkg⍙PAGER ⍕h1⍪h2⍪(⊂[2](5 3⍴'???LBLVARFUNOPR')[k+⎕io;]),[1.5]n
Replacing the above with these two lines works:
zz←(5 3⍴'???LBLVARFUNOPR')[k+⎕io;]
pkg⍙PAGER ⍕h1⍪h2⍪(⊂[2]zz),[1.5]n
Which is the same thing except for replacing a subexpression with a variable.
--
"The secret to creativity is knowing how to hide your sources."
Albert Einstein