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Re: [Axiom-developer] Question concerning types...
From: |
Ralf Hemmecke |
Subject: |
Re: [Axiom-developer] Question concerning types... |
Date: |
Sun, 17 Sep 2006 02:33:19 +0200 |
User-agent: |
Thunderbird 1.5.0.5 (X11/20060719) |
The problem, as described to me, was having three matrices A, B and C.
C is known. The goal was to choose the elements of one of A or B then
look for equations coming from AB-BA = C. The elements of A and B are
quaternion.
Maybe you want that... Add the C yourself.
The trick is that you add variables if form of polynomials.
)clear all
R := Fraction Integer
P := Polynomial R
Q := Quaternion P
M := Matrix Q
A1 := quatern(A11, A1i, A1j, A1k)
A2 := quatern(A21, A2i, A2j, A2k)
A3 := quatern(A31, A3i, A3j, A3k)
A4 := quatern(A41, A4i, A4j, A4k)
A: M := matrix [[A1, A2], [A3, A4]]
B1: Q := quatern( 1, 2, 3, 5)
B2: Q := quatern( 7, 11, 13, 17)
B3: Q := quatern(19, 23, 29, 31)
B4: Q := quatern(37, 41, 43, 47)
B: M := matrix [[B1, B2], [B3, B4]]
Z := A*B - B*A
Ralf
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- Re: [Axiom-developer] Question concerning types..., Gabriel Dos Reis, 2006/09/17
- Re: [Axiom-developer] Question concerning types..., Martin Rubey, 2006/09/17
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- RE: [Axiom-developer] Question concerning types..., Bill Page, 2006/09/17
- Re: [Axiom-developer] Question concerning types...,
Ralf Hemmecke <=
- RE: [Axiom-developer] Question concerning types..., Bill Page, 2006/09/17
- Re: [Axiom-developer] Question concerning types..., Gabriel Dos Reis, 2006/09/17
- Re: [Axiom-developer] Question concerning types..., Ralf Hemmecke, 2006/09/17
- Re: [Axiom-developer] Question concerning types..., Gabriel Dos Reis, 2006/09/17
- Re: [Axiom-developer] Question concerning types..., Ralf Hemmecke, 2006/09/17
- Re: [Axiom-developer] Question concerning types..., Gabriel Dos Reis, 2006/09/17
- Re: [Axiom-developer] Question concerning types..., Ralf Hemmecke, 2006/09/18
- Re: [Axiom-developer] Question concerning types..., Gabriel Dos Reis, 2006/09/18
- Re: [Axiom-developer] Question concerning types..., Ralf Hemmecke, 2006/09/18
- [Axiom-developer] equal or unequal (was: Question concerning types...), Ralf Hemmecke, 2006/09/18