[Axiom-developer] [recurrence relation operator]

[unknown]

Changes 
http://page.axiom-developer.org/zope/mathaction/RecurrenceRelationOperator/diff
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  *  I don't think that the following can be justified mathematically:

\begin{axiom}
sum(k,k=1.0..2.5)
\end{axiom}

In the absence of a delta, what do you expect? Axiom simply apply the general 
formula for

\begin{axiom}
sum(k,k=1..n)
subst(%,n=2.5)
\end{axiom}
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forwarded from http://page.axiom-developer.org/zope/mathaction/address@hidden