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Re: Automake,cygwin: 'make clean' with libtool wrappers...


From: Charles Wilson
Subject: Re: Automake,cygwin: 'make clean' with libtool wrappers...
Date: Mon, 06 May 2002 04:07:45 -0400
User-agent: Mozilla/5.0 (Windows; U; Windows NT 5.0; en-US; rv:0.9.4) Gecko/20011019 Netscape6/6.2

Alexandre Duret-Lutz wrote:

[I haven't read the whole thread.]

I understand what both `foo.$(EXEEXT)' and `foo' need to be
erased, but I fail to see the point in cleaning `.libs/':
doesn't clean-libtool already do that?  (I think people aren't
expected to call clean-binPROGRAMS, are they?)


I wasn't sure of the correct protocol: should clean-binPROGRAMS clean *everything* related to programs, or just the stuff that other rules wouldn't also catch?

Now that I think about it, probably the latter: you don't expect clean-binPROGRAMS to clean up all of the .o's and .lo's that were used to build the programs...so it makes sense to let clean-libtool handle the .libs/_libs subdirectory.


Also, for simplicity I suggest dropping `test -f' and erasing
all files in a single `rm -f' call:

 .PHONY clean-am: clean-%DIR%PROGRAMS
 clean-%DIR%PROGRAMS:
-       -test -z "$(%DIR%_PROGRAMS)" || rm -f $(%DIR%_PROGRAMS)
+?!LIBTOOL?        -test -z "$(%DIR%_PROGRAMS)" || rm -f $(%DIR%_PROGRAMS)
+?LIBTOOL?      @list='$(%DIR%_PROGRAMS)'; for p in $$list; do \
+?LIBTOOL?        f=`echo $$p|sed 's/$(EXEEXT)$$//'`; \
+?LIBTOOL?        echo " rm -f $$p $$f"; \
+?LIBTOOL?        rm -f $$p $$f ; \
+?LIBTOOL?      done


If this is accepted, I'd be perfectly happy.

--Chuck




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